Hi team, I am looking at the answer from the last practical in the Statistics module and I am slightly confused by the P-value you have (0.51) Please could you let me know what degrees of freedom you used? I input 0.66 T-score and 173 degrees of freedom into the P value calculator and got 0.26. I must be doing something wrong. Many thanks
You are almost there!
The one-tailed p-value in this case is 0.26 (the answer that you got).
The two-tailed p-value (which we actually need) is 0.51 – as suggested in the answer.
The 365 Team