why it gives me that the syntax is invalid Create a while loop that will print all odd numbers from 0 to 30 on the same row. <br /> *Hint: There are two ways in which you can create the odd values!* x = 0 while x % 2 = 1: print (x, end = " ") x <= 30

Hi Yousof! Thanks for reaching out. This is because the single equal sign (=) is used for assigning a value to a variable and when you want to compare some values you should use the double equal sign (==). It seems that you want to print all odd numbers from 1 to 30. Please, use the following code: x = 0 while x <= 30: if x % 2 == 1: print(x, end = " ") x += 1 Hope this helps. Best, Tsvetelin

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Yousof Mohey

Last answered:

29 Nov 2022

Posted on:

20 Nov 2022

problem in the excersice

in Introduction to Python / Using While Loops and Incrementing

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Tsvetelin Tsonkov

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Posted on:

29 Nov 2022

problem in the excersice

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