In the following snippet, I tried the same with int x =100 but I got an error but when I tried the same thing without int it worked. Now I know Python got some features but technically speaking don't you think that my approach was right? x = 100if x>100 :print("A busy day")else:print("A calm day")

Hi Archisman, You have probably resolved the issue by now. However, I was able to get your code to execute by indenting each print statement as follows. x = 100 if x > 100: print("A busy day") else: print("A calm day") Python requires the line(s) after the conditional statements must be indented. I hope this helps. Anderson

Hi Archisman! Thanks for reaching out. Generally, Python is extremely good at guessing the type of variables you are using. Should you wish to be specific, you can use the built-in functions, such as int() or float(). Hope this helps.Best,Martin

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Archisman Das

Last answered:

14 Aug 2020

Posted on:

05 Aug 2020

Basic Python Syntax

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Martin Ganchev

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09 Aug 2020

Anderson Phillips

Posted on:

14 Aug 2020

Basic Python Syntax

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