Hello. I'm curious about other students' solution in this challenge. I always try to solve the challenges with the least lines that I could, only to find out later that Giles perform the solution with even fewer lines of code. Here's mine: n = 1000 coins = [1 for i in range(n)] for i in range(1,n): for j in range(1,n): if (j+1) % (i+1) == 0: if coins[j] == 1: coins[j] = 0 else: coins[j] = 1 result = [num+1 for num in range(len(coins)) if coins[num] == 1] print(result) I think being able to understand codes written by other people is also a good practice. Would you care to share your solution?

Here's my code...thank you for sharing yours def coins(n): l1= ["H" for i in range(n)] for a in range(0,n): for i in range(a+1,n,a+2): if l1[i] == "H": l1[i] = "T" else: l1[i] = "H" index = [count+1 for count,ele in enumerate(l1) if ele=="H"] print(index) coins(100)

here's mine, a bit more complex but it works! list_coins = ['head' for i in range(1000)] list_heads = [] jump = 1 count = 1 # print(list_coins) while jump < len(list_coins): jump += 1 for j in range((jump-1),(len(list_coins)),jump): # print(f'jump is {jump}') if list_coins[j] == 'head': list_coins[j] = 'tail' elif list_coins[j] == 'tail': list_coins[j] = 'head' # print(list_coins) # print(list_coins) for c in list_coins: if c == 'head': list_heads.append(count) count += 1 print(list_heads)

Here's how I did mine. coins = {} for i in range(1, 21): coins[i] = "heads" def coin_flip(coin_dict): step = 2 while step <= len(coin_dict): for i in range(step, len(coin_dict)+1, step): coin = coin_dict[i] if coin == "heads": coin_dict[i] = "tails" else: coin_dict[i] = "heads" step += 1 coin_flip(coins) print(coins) I think it would make more sense if I did the dictionary part in the function and have it take the number of coins as the parameter but it works.

I couldn't figure out the dictionary part, but here is the code I used to flip the coins. It made the most sense to me to use the modulus operator to iterate through all the indices that were divisible by 2, 3, 4, etc. n = 1001 #create a list with 1000 0s coins = [0]*n for i in range(0, n): for j in range(1, n): if i % j == 0: coins[i] = 1 - coins[i]