Find the probability of getting a spade on either the first turn or the second turn Event A: Drawing a spade Event B: Drawing a spade P(A) = 13/52=0.25 P(B) = 13/52=0.25 P(A|B) = 12/51 ~ 0.2353 P(AUB) = P(A) + P(B) - P(A∩B) [Additive Law] = P(A) + P(B) - P(A|B) * P(B) [Multiplication Law] = 0.25 + 0.25 - 0.2353*0.25 = 0.5 - 0.0588 = 0.4412 Is it a correct answer?

Hey Eslam, Thank you for reaching out! Note that the task asks for the probability of drawing a spade on either the first turn or the second turn. This means we need to study the following 2 cases: Case 1: Drawing a spade on the first turn and not drawing a spade on the second turn. Case 2: Not drawing a spade on the first turn and drawing a spade on the second turn. Find the probabilities of both of these cases, sum them up, and you'll find the probability of drawing either on the first, or on the second turn. Another approach to solve the same problem is to instead consider the following 2 cases: Case 1: Drawing a spade on both the first and the second turn. Case 2: Drawing a spade on neither the first, nor the second turn. Find the probabilities of both of these cases, sum them up, find their complement, and you should obtain the same result as the first approach. Hope this helps! Kind regards, 365 Hristina

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Eslam Mohamed Helmi

Last answered:

06 Jan 2023

Posted on:

05 Jan 2023

Lecture Homework Solution

in Probability / Multiplication Rule

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Hristina Hristova

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Posted on:

06 Jan 2023

Lecture Homework Solution

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