Hi, I'm running the following code for question 3: user_input = input("Please enter a number between 1 and 12: /n > ") while (not user_input.isdigit()) or (int(user_input)) < 1 or int(user_input) > 12: print("Must be an integer between 1 and 12.") user_input = int(input("Please select a number between 1 and 12. /n > ")) print("======================================") print() print(f"This is the {user_input} times table:") print() for i in range(1,13): print(f"{i} x {user_input} = {i*user_input}") But I am getting this instead: This is the 7 times table: 1 x 7 = 7 2 x 7 = 77 3 x 7 = 777 4 x 7 = 7777 5 x 7 = 77777 6 x 7 = 777777 7 x 7 = 7777777 8 x 7 = 77777777 9 x 7 = 777777777 10 x 7 = 7777777777 11 x 7 = 77777777777 12 x 7 = 777777777777 Any ideas?

Hey João, Thank you for your question! Notice that you define the variable user_input in two different ways. The one outside the while-loop is a string while the one inside the loop is an integer. This causes two problems: 1. Try entering an invalid integer twice. You should get the following error: The reason is as follows. Let's say you enter a 0 the first time (which, remember, is a string). The while-loop check if this string is actually a digit. It is, so it moves on to the second condition which checks if the digit is smaller than 1. It is, so you enter the loop. Now, the second time you enter a 0 (which is now directly converted to an integer), you again need to go through the conditions of the while-loop. First, you check whether your integer is ... an integer :) As it turns out, integers don't have the attribute isdigit(), so an error is thrown. The remedy is to define user_input as a string in both cases, namely: user_input = input("Please enter a number between 1 and 12: /n > ") while (not user_input.isdigit()) or (int(user_input)) < 1 or int(user_input) > 12: print("Must be an integer between 1 and 12.") user_input = input("Please select a number between 1 and 12. /n > ") 2. The second trouble is the following. In the lucky occasion of entering a valid input from the first time, you won't enter the while-loop. Therefore, user_input will be left as a string. The command {i*user_input} inside the very last print function multiplies this string i times. This translates into printing out the number i many times. Modifying the print function as follows should solve the problem: print(f"{i} x {user_input} = {i*int(user_input)}") Hope this helps! Keep up the good work! Kind regards, 365 Hristina