Question 3 instead of multiplying it is adding characters

Hey João,

Thank you for your question!

Notice that you define the variable user_input in two different ways. The one outside the while-loop is a string while the one inside the loop is an integer. This causes two problems:
1. Try entering an invalid integer twice. You should get the following error:

The reason is as follows. Let's say you enter a 0 the first time (which, remember, is a string). The while-loop check if this string is actually a digit. It is, so it moves on to the second condition which checks if the digit is smaller than 1. It is, so you enter the loop. Now, the second time you enter a 0 (which is now directly converted to an integer), you again need to go through the conditions of the while-loop. First, you check whether your integer is ... an integer :) As it turns out, integers don't have the attribute isdigit(), so an error is thrown. The remedy is to define user_input as a string in both cases, namely:

user_input = input("Please enter a number between 1 and 12: /n > ")
while (not user_input.isdigit()) or (int(user_input)) < 1 or int(user_input) > 12:
    print("Must be an integer between 1 and 12.")
    user_input = input("Please select a number between 1 and 12. /n > ")

2. The second trouble is the following. In the lucky occasion of entering a valid input from the first time, you won't enter the while-loop. Therefore, user_input will be left as a string. The command {i*user_input} inside the very last print function multiplies this string i times. This translates into printing out the number i many times. Modifying the print function as follows should solve the problem:

print(f"{i} x {user_input} = {i*int(user_input)}")

Hope this helps! Keep up the good work!

Kind regards,
365 Hristina

Awesome! Thanks a lot!!