Resolved: Question about output isolation in exercise 8.6 iteration of dictionaries?

Hi Panagiotis!
Thanks for reaching out.

You can use something like this:

prices = {
    "box_of_spaghetti" : 4,
    "lasagna" : 5,
    "hamburger" : 2
}

quantity = {
    "box_of_spaghetti" : 6,
    "lasagna" : 10,
    "hamburger" : 0
}

money_spent=0

for i in prices:
   
    if prices[i] >= 5:
        money_spent += prices[i] * quantity[i]
        
print("The products of 5 dollars or above costed", money_spent)

If you add the second condition in this loop, every time it has a price less than 5, it will print you the message.

Hope this helps.
Best,
Tsvetelin

Thank you professor i found the solution. I nest the next if conditional, out of the for loop. like that: 

for i in prices:

    if prices[i] >= 5:

        mon_spent_up5 += prices[i] * quantity[i]

        print("The products of 5 dollars or above costed:", mon_spent_up5)

if mon_spent_up5 == 0:

        print("No product was in that price range.")

Thus if after all iterations it is still 0, it gives back "No product was in that price range". Cause when i was nesting it in the initial loop, it always gave at least the first iteration as a "No product in range", because  the first in the dictionary, it was a sub 5 product. Thanks for your input.