Hello,

I’ve practiced with your files, but i’ve faced with some problems.

I can not understand the process of the below program

n = [1,2,3,4,5,6]

for x in range(len(n)):

print(n[x] * 10, end = ” “)

Output :

10 20 30 40 50 60

how can the output like above come out?

I guess,

n = [1,2,3,4,5,6]

len(n)

this output must be 6

and list(range(len(n)))

this output must be

0, 1, 2, 3, 4, 5

then i think the value of x contains range(len(n)) (0,1,2,3,4,5)

and the output should be 0,10,20,30,40,50

i can't just understand how this program works!

and i would like to ask for this statement : print(n[x] * 10, end = " ")

why should i write down n[x]?

or.. I guess n[x] that could be slicing?

can you explain it ?

thanks for reading

Daehyeon Kim

Hi Daehyeon!

Thanks for reaching out.

Please accept my apologies for the delayed response.

This is a great question, indeed! In fact, you’ve nearly found out the explanation you are looking for, you have correctly pointed the problem.

When you are referring to **n[x]**, think of indexing in Python. Moreover, we obtain the value of x from the sequence of numbers generated by the range() function (that you have correctly said becomes 0, 1, 2, 3, 4, 5).

Therefore, it turns out we want to print n[0], n[1], …, n[5], which start by the 0-th element from the list **n** (i.e. the element at position 1 from the list **n**), which is the value of 1. Hence, the output of n[x] * 10 for the first element equals n[0] * 10 = 1 * 10 = 10.

The next element is at position 2, written as n[1], which is the values of 2. Hence, the relevant output is 20. And so on until we eventually obtain 50 and the loop ends.

Apparently, this operation may look a little confusing at first, but this is a great exercise to think over it until you say you’ve understood how a loop works. In addition, it is great that you want to look into such level of detail. Keep up the pace and interest and I am sure that after completing the different Python units in the program you will become an independent Python user!

Hope this helps.

Best,

Martin

It was really helpful! thanks for your answer

Thank you very much as well! Best, Martin