Resolved: Questions about the transformation function
On the line:
a,b = trans((a,b))
I understand that the p becomes (a,b), but what happens next?
Ler's say we take trans_3
. Can someone explains what happens inside the function when we call trans_3((a,b))
?
2 answers ( 1 marked as helpful)
Hey Bondan,
Thank you for your question!
Let me suggest a modification to the code, where I have included 3 print
-statements on lines 6, 14, 22, and 37.
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Then, let's study the
for
-loop on lines 31-35, where I have reduced the number of iterations to 3.On line 32, we assign the variable
trans
one of the 3 functions - trans_1
, trans_2
, or trans_3
. From the output, we can see that the choice during the first iteration was trans_3
. On line 33, we modify the integers a
and b
using the function trans_3
. What happens in this function is the following:1. The variable
p
represents the tuple (a, b)
2. Line 18 -
x
equals the first item in p
, namely a
3. Line 19 -
y
equals the second item in p
, namely b
4. Line 20 -
x1
is computed according to Transformation 3, using variable x
5. Line 21 -
y1
is computed according to Transformation 3, using variable y
6. Line 23 - the function returns the variables
x1
and y1
in a tupleGoing back to line 33, variable
a
is assigned the value x1
while variable b
is assigned the value y1
. These are then appended to the lists a1
and b1
, respectively.Then, the second iteration comes, where, this time, the function
trans_1
is chosen. The whole procedure from above repeats.Finally,
trans_3
is chosen again during the third iteration.
Hope this helps!
Kind regards,
365 Hristina
Oh I get it now! It's like calling multiple items wtih one variable. Thank you for the answer Hristina