Relationship between combination, variation and permutation without repetition
considering combinatorics without repetition, the relation states that C = V/P. If P = n! and V = n!/(n-p)!
then how is C = n!/p!(n-p)!? Can you explain why it is not 1/(n-p)! if you substitute the formula for V and P?
1 answers ( 0 marked as helpful)
Hey C,
If you go back to the Permutation formula, it's defined as P(n) = n!. In that case p = n, so we only use one variable (since it makes more sense). In reality, it's equivalent to p!.
Hence, C = V/P = (n!/(n-p)!) / (p!) = n! / ((n-p)! p!).
Hope this helps!
Best,
365 Vik
Submit an answer
