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use .loc vs not using .loc?
Let's take a look at the following codes:
# First Code
temp = df_purchase_predictors[df_purchase_predictors['Brand'] == 1]
temp.loc[:, 'Revenue Brand 1'] = temp['Price_1'] * temp['Quantity']
temp
versus:
# Second Code
temp1 = df_purchase_predictors[df_purchase_predictors['Brand'] == 1]
temp1['Revenue Brand 1'] = temp1['Price_1'] * temp1['Quantity']
temp1
The only difference is using loc or not.
and it returned exactly the same table.
is there any difference?
1 answers ( 0 marked as helpful)
ChatGPT says:
"
The key difference between the two lines of code lies in how the target DataFrame is referenced:
-
temp.loc[:, 'Revenue Brand 1']
:- This explicitly selects all rows (
:
) and only the'Revenue Brand 1'
column. It is useful when you want to modify a specific column while keeping the structure of the DataFrame intact, avoiding the creation of new columns in some cases.
- This explicitly selects all rows (
-
temp1['Revenue Brand 1']
:- This directly references (or creates) the
'Revenue Brand 1'
column intemp1
. If it doesn't exist, it will be created.
- This directly references (or creates) the
Both approaches work for creating a new column but loc
can be more flexible in complex scenarios (like modifying slices).
"
Given this is a new column, 2. seems better than 1. to me.