Binary Search alternate solution

my_list = [1,2,3,4,67,89]
item = 89

def binary_searach(my_list,item):
    found = False
    
    while found == False and len(my_list) > 0:
        list_midpoint = len(my_list)/2
        if item == my_list[int(list_midpoint)]:
            found = True
        elif item > my_list[int(list_midpoint)]:
            my_list = my_list[int(list_midpoint)+1:len(my_list)]
        else:
            my_list = my_list[0:int(list_midpoint)]
            
    return found
            
            
print(binary_searach(my_list, item))