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Other Solutions
Here are three solution that worked for me, I found one mentioned above
# Using distinct ##
##############
SELECT distinct ee.*
FROM emp_manager ee
JOIN emp_manager eM ON ee.emp_no = eM.manager_no;
# Using Subqueries nested in WHERE ##
###############################
SELECT ee.*
FROM emp_manager ee
WHERE ee.emp_no IN (SELECT distinct manager_no FROM emp_manager);
## Using GROUP BY ############
############################
SELECT ee.emp_no, eM.manager_no
FROM emp_manager ee
JOIN emp_manager eM ON ee.emp_no = eM.manager_no
GROUP BY ee.emp_no;
1 answers ( 0 marked as helpful)
Hi Sahar!
Thanks for reaching out.
Yes, these are alternatives solutions. The second one contains 4 rows which are two by two the same.
Hope this helps.
Best,
Tsvetelin