A = [14,13,12,12,11,10,9,8,7,6,5,4,3,2,1] B = [] C = [] count = 0 def towers_of_hanoi (A,B,C,n): global count if n == 1: disk = A.pop() C.append(disk) count = count + 1 else: towers_of_hanoi (A,C,B,n-1) towers_of_hanoi (A,B,C,1) towers_of_hanoi (B,A,C,n-1) return count towers_of_hanoi (A,B,C,14) 16383 A [14] B [] C [13, 12, 12, 11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1]

Hey Ashakah, Thank you for your question! It appears that list A has the value 12 twice - remove one of them and everything should be in order :) Kind regards, 365 Hristina

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Ashakah Onome Andrew

Last answered:

24 Nov 2021

Posted on:

22 Nov 2021

Tower of Hanoi problem _ Tower "A" is not Empty and Tower "C" has incomplete disk . Please why?

in Python Programmer Bootcamp / Code for Tower of Hanoi

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Hristina Hristova

Instructor

Posted on:

24 Nov 2021

Tower of Hanoi problem _ Tower "A" is not Empty and Tower "C" has incomplete disk . Please why?

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