In line 107, I think it should be: ... .get(letter.lower(),0)+1. Is that's correct?. Otherwise, it will just keep updating the count of a letter and force it to 1 whenever the uppercase appears.

Hey Mohammed, Thank you very much for your question! You are correct! The line should indeed read ... .get(letter.lower(), 0) + 1 Implementing it in this way yields the same result as the one obtained when using the Counter class, shown a few lectures later. And that's how it should be. Kind regards, 365 Hristina

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Mohammed Osailan

Last answered:

20 Apr 2022

Posted on:

20 Apr 2022

Resolved: in line 107, I think it should be: ... .get(letter.lower(),0)+1. Is that's correct?

in Python Programmer Bootcamp / Dictionaries

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Hristina Hristova

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Posted on:

20 Apr 2022

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Resolved: in line 107, I think it should be: ... .get(letter.lower(),0)+1. Is that's correct?

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