12 Oct 2022

Posted on:

15 Nov 2021

0

# Last question in the exercise file

Hi!

In the last question, "What is the likelihood of getting admitted, having been offered a place on the waitlist?", the way it's calculated in the solutions is 33/1299. As I understand, that's because the numerator is 33/1299 and the denominator 1299/1299 right?
However, the way I calculated is (33/1299)/(1299/5678), so I divided intersection over the probability of being offered a place on the waitlist for all the students. Is this approach wrong?

Instructor
Posted on:

16 Nov 2021

0

Hey Avtandil,

As the question asks, we would like to find the likelihood of being admitted to the college given that you have been offered a place on the waiting list. The number of students who have been offered a place on the waiting list is 1299. Out of these 1299, 33 students have been admitted. Therefore, there is a 33/1299 chance of being admitted given that you have been offered a place on the waiting list.

To answer your question: for this exercise, we don't actually need the probability of being offered a place on the waiting list (1299/5678). We start with the assumption that we are already on the waiting list and what we need is the probability of being admitted :)

Hope this helps!

Kind regards,
365 Hristina

Posted on:

11 Oct 2022

0

i have also solved this using simple probability formula of number of favorable outcomes/total no of outcomes using 33/1299.

But can this also be solved using conditional probability formula?  P (Being Admitted | offered a placed on the waitlist).

As this also involved condition to find probability, why cannot we use the Bayes rule here?

Instructor
Posted on:

12 Oct 2022

0

Hey Sandesh,