Sixth question of the practice exam
I don't understand why if the frequency with which the family cars pass is equal to 3 then the mean is 1/3. Why is it that the sum of the passing cars is not simply the sum of the frequencies?
check out the video "exponential Distribution" in section 5 of the course, That helped me understand the expected value for exponential distribution is 1/landa.
so the sum of exponential distributions' expected values would be 1/3 + 1/8.
It looks there is a mistake in the last question. Your are given expected frequencies of two types of cars. 3 and 8 respectively You have been told it follows Poison distribution. 3 per time period and 8 per time period. The answer should be 11.
Here is my take on this.
"the sum of the number of family cars and the number of single-member cars" shall increase as the number of family cars and the number of single-member cars increase.
"1/3 + 1/8" does not behave so therefore this cannot be the right answer
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